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4902493173481 = 19258025956499
BaseRepresentation
bin100011101010111001101…
…0111010011011011101001
3122100200012011211010020001
41013111303113103123221
51120310301223022411
614232101350503001
71014123231261031
oct107256327233351
918320164733201
104902493173481
111620154652612
12672177064a61
132973c2c63a07
1412d3d38ba8c1
15877d2314dc1
hex475735d36e9

4902493173481 has 4 divisors (see below), whose sum is σ = 5160519130000. Its totient is φ = 4644467216964.

The previous prime is 4902493173439. The next prime is 4902493173541. The reversal of 4902493173481 is 1843713942094.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4902493173481 - 229 = 4901956302569 is a prime.

It is a super-2 number, since 2×49024931734812 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4902493173581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129012978231 + ... + 129012978268.

It is an arithmetic number, because the mean of its divisors is an integer number (1290129782500).

Almost surely, 24902493173481 is an apocalyptic number.

It is an amenable number.

4902493173481 is a deficient number, since it is larger than the sum of its proper divisors (258025956519).

4902493173481 is a wasteful number, since it uses less digits than its factorization.

4902493173481 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 258025956518.

The product of its (nonzero) digits is 5225472, while the sum is 55.

The spelling of 4902493173481 in words is "four trillion, nine hundred two billion, four hundred ninety-three million, one hundred seventy-three thousand, four hundred eighty-one".

Divisors: 1 19 258025956499 4902493173481