Base | Representation |
---|---|
bin | 101101101011100000… |
… | …001100101100111001 |
3 | 11200121020220220110122 |
4 | 231223200030230321 |
5 | 1300422322234001 |
6 | 34311002023025 |
7 | 3354314121002 |
oct | 555340145471 |
9 | 150536826418 |
10 | 49048243001 |
11 | 1988a4aaa1a |
12 | 960a1a7a75 |
13 | 48188242c4 |
14 | 25341801a9 |
15 | 1421042b1b |
hex | b6b80cb39 |
49048243001 has 4 divisors (see below), whose sum is σ = 49065389604. Its totient is φ = 49031096400.
The previous prime is 49048242979. The next prime is 49048243003. The reversal of 49048243001 is 10034284094.
49048243001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 25504409401 + 23543833600 = 159701^2 + 153440^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49048243001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49048243003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8569010 + ... + 8574731.
It is an arithmetic number, because the mean of its divisors is an integer number (12266347401).
Almost surely, 249048243001 is an apocalyptic number.
It is an amenable number.
49048243001 is a deficient number, since it is larger than the sum of its proper divisors (17146603).
49048243001 is a wasteful number, since it uses less digits than its factorization.
49048243001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17146602.
The product of its (nonzero) digits is 27648, while the sum is 35.
The spelling of 49048243001 in words is "forty-nine billion, forty-eight million, two hundred forty-three thousand, one".
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