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49065969473 = 75916463703
BaseRepresentation
bin101101101100100011…
…110100011101000001
311200122111021111121122
4231230203310131001
51300441342010343
634312434002025
73354620600453
oct555443643501
9150574244548
1049065969473
11198995080a4
129614116315
13481c3bc941
1425366762d3
151422895068
hexb6c8f4741

49065969473 has 4 divisors (see below), whose sum is σ = 49072440768. Its totient is φ = 49059498180.

The previous prime is 49065969467. The next prime is 49065969509. The reversal of 49065969473 is 37496956094.

49065969473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 49065969473 - 24 = 49065969457 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (49065969413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3224261 + ... + 3239442.

It is an arithmetic number, because the mean of its divisors is an integer number (12268110192).

Almost surely, 249065969473 is an apocalyptic number.

It is an amenable number.

49065969473 is a deficient number, since it is larger than the sum of its proper divisors (6471295).

49065969473 is an equidigital number, since it uses as much as digits as its factorization.

49065969473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6471294.

The product of its (nonzero) digits is 44089920, while the sum is 62.

The spelling of 49065969473 in words is "forty-nine billion, sixty-five million, nine hundred sixty-nine thousand, four hundred seventy-three".

Divisors: 1 7591 6463703 49065969473