Base | Representation |
---|---|
bin | 10110010100000101100000… |
… | …01101110100011110000011 |
3 | 20102201220210110220121010221 |
4 | 23022002300031310132003 |
5 | 22412420110134133212 |
6 | 252205455453003511 |
7 | 13223044131024151 |
oct | 1312026015643603 |
9 | 212656713817127 |
10 | 49068662802307 |
11 | 146a89a2a30905 |
12 | 5605a03a83597 |
13 | 214c202841955 |
14 | c18d163723d1 |
15 | 5a15c641c807 |
hex | 2ca0b0374783 |
49068662802307 has 8 divisors (see below), whose sum is σ = 50655512550272. Its totient is φ = 47482062408000.
The previous prime is 49068662802301. The next prime is 49068662802317. The reversal of 49068662802307 is 70320826686094.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49068662802307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49068662802301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61938444 + ... + 62725657.
It is an arithmetic number, because the mean of its divisors is an integer number (6331939068784).
Almost surely, 249068662802307 is an apocalyptic number.
49068662802307 is a deficient number, since it is larger than the sum of its proper divisors (1586849747965).
49068662802307 is a wasteful number, since it uses less digits than its factorization.
49068662802307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124676829.
The product of its (nonzero) digits is 41803776, while the sum is 61.
The spelling of 49068662802307 in words is "forty-nine trillion, sixty-eight billion, six hundred sixty-two million, eight hundred two thousand, three hundred seven".
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