Base | Representation |
---|---|
bin | 101101101101100101… |
… | …010000111111101011 |
3 | 11200200200120010120220 |
4 | 231231211100333223 |
5 | 1301010240010424 |
6 | 34314245421123 |
7 | 3355216453644 |
oct | 555545207753 |
9 | 150620503526 |
10 | 49083125739 |
11 | 198a816592a |
12 | 9619a0a7a3 |
13 | 4822b1888b |
14 | 2538a606cb |
15 | 1424133579 |
hex | b6d950feb |
49083125739 has 16 divisors (see below), whose sum is σ = 65770988544. Its totient is φ = 32558752800.
The previous prime is 49083125701. The next prime is 49083125783. The reversal of 49083125739 is 93752138094.
It is not a de Polignac number, because 49083125739 - 212 = 49083121643 is a prime.
It is a super-2 number, since 2×490831257392 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49083125691 and 49083125700.
It is not an unprimeable number, because it can be changed into a prime (49083120739) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3456057 + ... + 3470229.
It is an arithmetic number, because the mean of its divisors is an integer number (4110686784).
Almost surely, 249083125739 is an apocalyptic number.
49083125739 is a deficient number, since it is larger than the sum of its proper divisors (16687862805).
49083125739 is a wasteful number, since it uses less digits than its factorization.
49083125739 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19858.
The product of its (nonzero) digits is 1632960, while the sum is 51.
The spelling of 49083125739 in words is "forty-nine billion, eighty-three million, one hundred twenty-five thousand, seven hundred thirty-nine".
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