491003349601 has 4 divisors (see below), whose sum is σ = 498331757872. Its totient is φ = 483674941332.

The previous prime is 491003349587. The next prime is 491003349619. The reversal of 491003349601 is 106943300194.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-491003349601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (491003349631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3664204035 + ... + 3664204168.

It is an arithmetic number, because the mean of its divisors is an integer number (124582939468).

Almost surely, 2^491003349601 is an apocalyptic number.

It is an amenable number.

491003349601 is a deficient number, since it is larger than the sum of its proper divisors (7328408271).

491003349601 is an equidigital number, since it uses as much as digits as its factorization.

491003349601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7328408270.

The product of its (nonzero) digits is 69984, while the sum is 40.

Adding to 491003349601 its reverse (106943300194), we get a palindrome (597946649795).

The spelling of 491003349601 in words is "four hundred ninety-one billion, three million, three hundred forty-nine thousand, six hundred one".