4910289818113 has 4 divisors (see below), whose sum is σ = 4910294364160. Its totient is φ = 4910285272068.

The previous prime is 4910289818099. The next prime is 4910289818131. The reversal of 4910289818113 is 3118189820194.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4910289818113 is a prime.

It is a super-2 number, since 2×4910289818113² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4910289818183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377056 + ... + 3156382.

It is an arithmetic number, because the mean of its divisors is an integer number (1227573591040).

Almost surely, 2^{4910289818113} is an apocalyptic number.

It is an amenable number.

4910289818113 is a deficient number, since it is larger than the sum of its proper divisors (4546047).

4910289818113 is a wasteful number, since it uses less digits than its factorization.

4910289818113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4546046.

The product of its (nonzero) digits is 995328, while the sum is 55.

The spelling of 4910289818113 in words is "four trillion, nine hundred ten billion, two hundred eighty-nine million, eight hundred eighteen thousand, one hundred thirteen".