Base | Representation |
---|---|
bin | 100011101110111010100… |
… | …0010010101001011101001 |
3 | 122101111102210002102122010 |
4 | 1013131311002111023221 |
5 | 1120430423424232044 |
6 | 14240044444150133 |
7 | 1014546625061514 |
oct | 107356502251351 |
9 | 18344383072563 |
10 | 4911111164649 |
11 | 1623877246968 |
12 | 673981238349 |
13 | 298167531681 |
14 | 12d9b0291d7b |
15 | 87b38bd3bb9 |
hex | 477750952e9 |
4911111164649 has 4 divisors (see below), whose sum is σ = 6548148219536. Its totient is φ = 3274074109764.
The previous prime is 4911111164543. The next prime is 4911111164719. The reversal of 4911111164649 is 9464611111194.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 4911111164649 - 216 = 4911111099113 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4911111164598 and 4911111164607.
It is not an unprimeable number, because it can be changed into a prime (4911111163649) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 818518527439 + ... + 818518527444.
It is an arithmetic number, because the mean of its divisors is an integer number (1637037054884).
Almost surely, 24911111164649 is an apocalyptic number.
It is an amenable number.
4911111164649 is a deficient number, since it is larger than the sum of its proper divisors (1637037054887).
4911111164649 is a wasteful number, since it uses less digits than its factorization.
4911111164649 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1637037054886.
The product of its digits is 186624, while the sum is 48.
The spelling of 4911111164649 in words is "four trillion, nine hundred eleven billion, one hundred eleven million, one hundred sixty-four thousand, six hundred forty-nine".
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