491134684340161 has 4 divisors (see below), whose sum is σ = 491706436010800. Its totient is φ = 490562932669524.

The previous prime is 491134684340119. The next prime is 491134684340171. The reversal of 491134684340161 is 161043486431194.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 491134684340161 - 2¹⁷ = 491134684209089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (491134684340171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285875834031 + ... + 285875835748.

It is an arithmetic number, because the mean of its divisors is an integer number (122926609002700).

Almost surely, 2^{491134684340161} is an apocalyptic number.

It is an amenable number.

491134684340161 is a deficient number, since it is larger than the sum of its proper divisors (571751670639).

491134684340161 is an equidigital number, since it uses as much as digits as its factorization.

491134684340161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 571751670638.

The product of its (nonzero) digits is 5971968, while the sum is 55.

The spelling of 491134684340161 in words is "four hundred ninety-one trillion, one hundred thirty-four billion, six hundred eighty-four million, three hundred forty thousand, one hundred sixty-one".