Base | Representation |
---|---|
bin | 100011101111110110001… |
… | …0001011010011101100011 |
3 | 122101200121012021102211201 |
4 | 1013133230101122131203 |
5 | 1120444023032412024 |
6 | 14241015144422031 |
7 | 1014650325415411 |
oct | 107375421323543 |
9 | 18350535242751 |
10 | 4913111607139 |
11 | 1624703465a1a |
12 | 67423b177917 |
13 | 2983c5b02258 |
14 | 12db1dc242b1 |
15 | 87c04632744 |
hex | 477ec45a763 |
4913111607139 has 4 divisors (see below), whose sum is σ = 4913352975024. Its totient is φ = 4912870239256.
The previous prime is 4913111607031. The next prime is 4913111607199. The reversal of 4913111607139 is 9317061113194.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4913111607139 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4913111607199) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120653407 + ... + 120694120.
It is an arithmetic number, because the mean of its divisors is an integer number (1228338243756).
Almost surely, 24913111607139 is an apocalyptic number.
4913111607139 is a deficient number, since it is larger than the sum of its proper divisors (241367885).
4913111607139 is a wasteful number, since it uses less digits than its factorization.
4913111607139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241367884.
The product of its (nonzero) digits is 122472, while the sum is 46.
The spelling of 4913111607139 in words is "four trillion, nine hundred thirteen billion, one hundred eleven million, six hundred seven thousand, one hundred thirty-nine".
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