Base | Representation |
---|---|
bin | 100011101111110111001… |
… | …1111111101000100101001 |
3 | 122101200200210120211122120 |
4 | 1013133232133331010221 |
5 | 1120444112114121403 |
6 | 14241023001341453 |
7 | 1014651261133665 |
oct | 107375637750451 |
9 | 18350623524576 |
10 | 4913148973353 |
11 | 1624722567795 |
12 | 67424b797889 |
13 | 29840078603a |
14 | 12db24b8d8a5 |
15 | 87c07a63e53 |
hex | 477ee7fd129 |
4913148973353 has 8 divisors (see below), whose sum is σ = 6550882214688. Its totient is φ = 3275424190464.
The previous prime is 4913148973309. The next prime is 4913148973357. The reversal of 4913148973353 is 3533798413194.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4913148973353 - 29 = 4913148972841 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4913148973357) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 605400 + ... + 3192617.
It is an arithmetic number, because the mean of its divisors is an integer number (818860276836).
Almost surely, 24913148973353 is an apocalyptic number.
It is an amenable number.
4913148973353 is a deficient number, since it is larger than the sum of its proper divisors (1637733241335).
4913148973353 is a wasteful number, since it uses less digits than its factorization.
4913148973353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4229223.
The product of its digits is 29393280, while the sum is 60.
The spelling of 4913148973353 in words is "four trillion, nine hundred thirteen billion, one hundred forty-eight million, nine hundred seventy-three thousand, three hundred fifty-three".
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