Base | Representation |
---|---|
bin | 101101110000101100… |
… | …000011101110010011 |
3 | 11200211022121201012221 |
4 | 231300230003232103 |
5 | 1301112110104120 |
6 | 34323350401511 |
7 | 3356421426562 |
oct | 556054035623 |
9 | 150738551187 |
10 | 49135238035 |
11 | 19924619644 |
12 | 9633360297 |
13 | 4830863560 |
14 | 2541947bd9 |
15 | 14289c90aa |
hex | b70b03b93 |
49135238035 has 8 divisors (see below), whose sum is σ = 63497846160. Its totient is φ = 36284483424.
The previous prime is 49135238029. The next prime is 49135238051. The reversal of 49135238035 is 53083253194.
49135238035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 49135238035 - 223 = 49126849427 is a prime.
It is a super-2 number, since 2×491352380352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49135237982 and 49135238000.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377963305 + ... + 377963434.
It is an arithmetic number, because the mean of its divisors is an integer number (7937230770).
Almost surely, 249135238035 is an apocalyptic number.
49135238035 is a deficient number, since it is larger than the sum of its proper divisors (14362608125).
49135238035 is a wasteful number, since it uses less digits than its factorization.
49135238035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 755926757.
The product of its (nonzero) digits is 388800, while the sum is 43.
The spelling of 49135238035 in words is "forty-nine billion, one hundred thirty-five million, two hundred thirty-eight thousand, thirty-five".
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