Base | Representation |
---|---|
bin | 1110010011001110001… |
… | …10101101011110100011 |
3 | 1201222021110011021211100 |
4 | 13021213012231132203 |
5 | 31022244124143011 |
6 | 1013420442045443 |
7 | 50333155542423 |
oct | 7114706553643 |
9 | 1658243137740 |
10 | 491356084131 |
11 | 17a423777580 |
12 | 7b28a1a9883 |
13 | 374473a4063 |
14 | 19ad3220483 |
15 | cbabd42d56 |
hex | 72671ad7a3 |
491356084131 has 12 divisors (see below), whose sum is σ = 774258072120. Its totient is φ = 297791566080.
The previous prime is 491356084097. The next prime is 491356084133. The reversal of 491356084131 is 131480653194.
491356084131 is a `hidden beast` number, since 4 + 9 + 1 + 3 + 5 + 608 + 4 + 1 + 31 = 666.
It is not a de Polignac number, because 491356084131 - 211 = 491356082083 is a prime.
It is a super-2 number, since 2×4913560841312 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (491356084133) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2481596286 + ... + 2481596483.
It is an arithmetic number, because the mean of its divisors is an integer number (64521506010).
Almost surely, 2491356084131 is an apocalyptic number.
491356084131 is a deficient number, since it is larger than the sum of its proper divisors (282901987989).
491356084131 is a wasteful number, since it uses less digits than its factorization.
491356084131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4963192786 (or 4963192783 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 45.
The spelling of 491356084131 in words is "four hundred ninety-one billion, three hundred fifty-six million, eighty-four thousand, one hundred thirty-one".
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