Base | Representation |
---|---|
bin | 1110010011010000100… |
… | …01110000100100100001 |
3 | 1201222022211011210202101 |
4 | 13021220101300210201 |
5 | 31022314143220401 |
6 | 1013422423450401 |
7 | 50333515011451 |
oct | 7115021604441 |
9 | 1658284153671 |
10 | 491375757601 |
11 | 17a433894543 |
12 | 7b2948b6a01 |
13 | 3744b4a1971 |
14 | 19ad5aa1d61 |
15 | cbad92c101 |
hex | 7268470921 |
491375757601 has 4 divisors (see below), whose sum is σ = 517237639600. Its totient is φ = 465513875604.
The previous prime is 491375757599. The next prime is 491375757637. The reversal of 491375757601 is 106757573194.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 491375757601 - 21 = 491375757599 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (491375757701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12930940971 + ... + 12930941008.
It is an arithmetic number, because the mean of its divisors is an integer number (129309409900).
Almost surely, 2491375757601 is an apocalyptic number.
It is an amenable number.
491375757601 is a deficient number, since it is larger than the sum of its proper divisors (25861881999).
491375757601 is a wasteful number, since it uses less digits than its factorization.
491375757601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25861881998.
The product of its (nonzero) digits is 5556600, while the sum is 55.
The spelling of 491375757601 in words is "four hundred ninety-one billion, three hundred seventy-five million, seven hundred fifty-seven thousand, six hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •