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49146900051 = 316382300017
BaseRepresentation
bin101101110001011000…
…100010111001010011
311200212010120012111110
4231301120202321103
51301123101300201
634324444344403
73356622520614
oct556130427123
9150763505443
1049146900051
1119930164477
129637245103
1348330b7762
142543301c0b
151429a2e6d6
hexb71622e53

49146900051 has 4 divisors (see below), whose sum is σ = 65529200072. Its totient is φ = 32764600032.

The previous prime is 49146900041. The next prime is 49146900149. The reversal of 49146900051 is 15000964194.

49146900051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 49146900051 - 210 = 49146899027 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49146899982 and 49146900009.

It is not an unprimeable number, because it can be changed into a prime (49146900041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8191150006 + ... + 8191150011.

It is an arithmetic number, because the mean of its divisors is an integer number (16382300018).

Almost surely, 249146900051 is an apocalyptic number.

49146900051 is a deficient number, since it is larger than the sum of its proper divisors (16382300021).

49146900051 is a wasteful number, since it uses less digits than its factorization.

49146900051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16382300020.

The product of its (nonzero) digits is 38880, while the sum is 39.

The spelling of 49146900051 in words is "forty-nine billion, one hundred forty-six million, nine hundred thousand, fifty-one".

Divisors: 1 3 16382300017 49146900051