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49225991257 = 396712408871
BaseRepresentation
bin101101110110000110…
…010000010001011001
311201001122101110020101
4231312012100101121
51301303323210012
634340351455401
73361603010332
oct556606202131
9151048343211
1049225991257
1119970874903
129659827561
1348465ba2a1
14254da0d289
151431953d57
hexb76190459

49225991257 has 4 divisors (see below), whose sum is σ = 49238404096. Its totient is φ = 49213578420.

The previous prime is 49225991207. The next prime is 49225991281. The reversal of 49225991257 is 75219952294.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49225991257 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49225991198 and 49225991207.

It is not an unprimeable number, because it can be changed into a prime (49225991207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6200469 + ... + 6208402.

It is an arithmetic number, because the mean of its divisors is an integer number (12309601024).

Almost surely, 249225991257 is an apocalyptic number.

It is an amenable number.

49225991257 is a deficient number, since it is larger than the sum of its proper divisors (12412839).

49225991257 is a wasteful number, since it uses less digits than its factorization.

49225991257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12412838.

The product of its digits is 4082400, while the sum is 55.

The spelling of 49225991257 in words is "forty-nine billion, two hundred twenty-five million, nine hundred ninety-one thousand, two hundred fifty-seven".

Divisors: 1 3967 12408871 49225991257