4925148035 has 4 divisors (see below), whose sum is σ = 5910177648. Its totient is φ = 3940118424.

The previous prime is 4925148031. The next prime is 4925148043. The reversal of 4925148035 is 5308415294.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4925148035 - 2² = 4925148031 is a prime.

It is a super-2 number, since 2×4925148035² = 48514166333328722450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4925147983 and 4925148001.

It is not an unprimeable number, because it can be changed into a prime (4925148031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 492514799 + ... + 492514808.

It is an arithmetic number, because the mean of its divisors is an integer number (1477544412).

Almost surely, 2^4925148035 is an apocalyptic number.

4925148035 is a deficient number, since it is larger than the sum of its proper divisors (985029613).

4925148035 is an equidigital number, since it uses as much as digits as its factorization.

4925148035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 985029612.

The product of its (nonzero) digits is 172800, while the sum is 41.

The square root of 4925148035 is about 70179.3989358701. The cubic root of 4925148035 is about 1701.4000041749.

The spelling of 4925148035 in words is "four billion, nine hundred twenty-five million, one hundred forty-eight thousand, thirty-five".