Base | Representation |
---|---|
bin | 10110011001011100111011… |
… | …00000100100001010101011 |
3 | 20110101112200112002211120110 |
4 | 23030232131200210022223 |
5 | 22423430202312333031 |
6 | 252430310352225403 |
7 | 13242262026663552 |
oct | 1314563540441253 |
9 | 213345615084513 |
10 | 49253032542891 |
11 | 1476a103934841 |
12 | 5635698b3b263 |
13 | 21637058830c8 |
14 | c23c0664ad99 |
15 | 5a62b7583c46 |
hex | 2ccb9d8242ab |
49253032542891 has 8 divisors (see below), whose sum is σ = 68525958320640. Its totient is φ = 31407730896872.
The previous prime is 49253032542881. The next prime is 49253032542949. The reversal of 49253032542891 is 19824523035294.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 49253032542891 - 211 = 49253032540843 is a prime.
It is a super-2 number, since 2×492530325428912 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (49253032542881) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 356906032851 + ... + 356906032988.
It is an arithmetic number, because the mean of its divisors is an integer number (8565744790080).
Almost surely, 249253032542891 is an apocalyptic number.
49253032542891 is a deficient number, since it is larger than the sum of its proper divisors (19272925777749).
49253032542891 is a wasteful number, since it uses less digits than its factorization.
49253032542891 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 713812065865.
The product of its (nonzero) digits is 18662400, while the sum is 57.
The spelling of 49253032542891 in words is "forty-nine trillion, two hundred fifty-three billion, thirty-two million, five hundred forty-two thousand, eight hundred ninety-one".
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