4930025113 has 4 divisors (see below), whose sum is σ = 5309257828. Its totient is φ = 4550792400.

The previous prime is 4930025081. The next prime is 4930025131. The reversal of 4930025113 is 3115200394.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3085580304 + 1844444809 = 55548^2 + 42947^2 .

It is a cyclic number.

It is not a de Polignac number, because 4930025113 - 2⁵ = 4930025081 is a prime.

It is a super-2 number, since 2×4930025113² = 48610295229621325538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4930022113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189616338 + ... + 189616363.

It is an arithmetic number, because the mean of its divisors is an integer number (1327314457).

Almost surely, 2^4930025113 is an apocalyptic number.

It is an amenable number.

4930025113 is a deficient number, since it is larger than the sum of its proper divisors (379232715).

4930025113 is a wasteful number, since it uses less digits than its factorization.

4930025113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 379232714.

The product of its (nonzero) digits is 3240, while the sum is 28.

The square root of 4930025113 is about 70214.1375579021. The cubic root of 4930025113 is about 1701.9614169500.

The spelling of 4930025113 in words is "four billion, nine hundred thirty million, twenty-five thousand, one hundred thirteen".