Base | Representation |
---|---|
bin | 101101111010100101… |
… | …101010010000010011 |
3 | 11201020220011012200201 |
4 | 231322211222100103 |
5 | 1301432120124021 |
6 | 34352042400031 |
7 | 3363506262520 |
oct | 557245522023 |
9 | 151226135621 |
10 | 49301333011 |
11 | 199aa354217 |
12 | 967ab00017 |
13 | 48590a92c8 |
14 | 2559a22147 |
15 | 1438387591 |
hex | b7a96a413 |
49301333011 has 16 divisors (see below), whose sum is σ = 58580408320. Its totient is φ = 40600880640.
The previous prime is 49301332933. The next prime is 49301333023. The reversal of 49301333011 is 11033310394.
49301333011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 49301333011 - 29 = 49301332499 is a prime.
It is a super-2 number, since 2×493013330112 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (49301333041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 787086 + ... + 847411.
It is an arithmetic number, because the mean of its divisors is an integer number (3661275520).
Almost surely, 249301333011 is an apocalyptic number.
49301333011 is a deficient number, since it is larger than the sum of its proper divisors (9279075309).
49301333011 is a wasteful number, since it uses less digits than its factorization.
49301333011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1634674.
The product of its (nonzero) digits is 2916, while the sum is 28.
The spelling of 49301333011 in words is "forty-nine billion, three hundred one million, three hundred thirty-three thousand, eleven".
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