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4931233679153 = 23214401464311
BaseRepresentation
bin100011111000010010001…
…1011101000011100110001
3122110102101011011002012002
41013300210123220130301
51121243131310213103
614253213311343345
71016161365451535
oct107604433503461
918412334132162
104931233679153
111631362944941
12677858221b55
1329a0234038a2
1413095c949bc5
15884155a0488
hex47c246e8731

4931233679153 has 4 divisors (see below), whose sum is σ = 5145635143488. Its totient is φ = 4716832214820.

The previous prime is 4931233679149. The next prime is 4931233679189. The reversal of 4931233679153 is 3519763321394.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4931233679153 - 22 = 4931233679149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4931233672153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107200732133 + ... + 107200732178.

It is an arithmetic number, because the mean of its divisors is an integer number (1286408785872).

Almost surely, 24931233679153 is an apocalyptic number.

It is an amenable number.

4931233679153 is a deficient number, since it is larger than the sum of its proper divisors (214401464335).

4931233679153 is a wasteful number, since it uses less digits than its factorization.

4931233679153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214401464334.

The product of its digits is 11022480, while the sum is 56.

The spelling of 4931233679153 in words is "four trillion, nine hundred thirty-one billion, two hundred thirty-three million, six hundred seventy-nine thousand, one hundred fifty-three".

Divisors: 1 23 214401464311 4931233679153