Base | Representation |
---|---|
bin | 1110010110111101110… |
… | …00000100001111010001 |
3 | 1202011110111020202110012 |
4 | 13023132320010033101 |
5 | 31040403032323441 |
6 | 1014352103044305 |
7 | 50434025436230 |
oct | 7133670041721 |
9 | 1664414222405 |
10 | 493365511121 |
11 | 180264a7283a |
12 | 7b74b140695 |
13 | 376a779c202 |
14 | 19c44050b17 |
15 | cc784689eb |
hex | 72dee043d1 |
493365511121 has 4 divisors (see below), whose sum is σ = 563846298432. Its totient is φ = 422884723812.
The previous prime is 493365511069. The next prime is 493365511127. The reversal of 493365511121 is 121115563394.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 493365511121 - 26 = 493365511057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (493365511127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35240393645 + ... + 35240393658.
It is an arithmetic number, because the mean of its divisors is an integer number (140961574608).
Almost surely, 2493365511121 is an apocalyptic number.
It is an amenable number.
493365511121 is a deficient number, since it is larger than the sum of its proper divisors (70480787311).
493365511121 is an equidigital number, since it uses as much as digits as its factorization.
493365511121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70480787310.
The product of its digits is 97200, while the sum is 41.
The spelling of 493365511121 in words is "four hundred ninety-three billion, three hundred sixty-five million, five hundred eleven thousand, one hundred twenty-one".
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