Base | Representation |
---|---|
bin | 10110011100011100100001… |
… | …11101100001001101101011 |
3 | 20110202101012121201022022021 |
4 | 23032032100331201031223 |
5 | 22432121341204304032 |
6 | 252545442113405311 |
7 | 13252563146345122 |
oct | 1316162075411553 |
9 | 213671177638267 |
10 | 49355901244267 |
11 | 147a97a1601722 |
12 | 5651607569837 |
13 | 217031a7c5487 |
14 | c28ba4696ab9 |
15 | 5a8cd8579097 |
hex | 2ce390f6136b |
49355901244267 has 8 divisors (see below), whose sum is σ = 49511949051456. Its totient is φ = 49199855644992.
The previous prime is 49355901244229. The next prime is 49355901244289. The reversal of 49355901244267 is 76244210955394.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 49355901244267 - 215 = 49355901211499 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49355901244297) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52173183 + ... + 53110759.
It is an arithmetic number, because the mean of its divisors is an integer number (6188993631432).
Almost surely, 249355901244267 is an apocalyptic number.
49355901244267 is a deficient number, since it is larger than the sum of its proper divisors (156047807189).
49355901244267 is a wasteful number, since it uses less digits than its factorization.
49355901244267 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1103957.
The product of its (nonzero) digits is 65318400, while the sum is 61.
The spelling of 49355901244267 in words is "forty-nine trillion, three hundred fifty-five billion, nine hundred one million, two hundred forty-four thousand, two hundred sixty-seven".
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