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4937112194009 = 19259848010211
BaseRepresentation
bin100011111011000001011…
…0100011000101111011001
3122110222112211121120120112
41013312002310120233121
51121342201210202014
614300024504334105
71016460146142032
oct107660264305731
918428484546515
104937112194009
1116338aa13a086
12678a18a74335
1329a74c275748
14130d59573a89
158865b6dc73e
hex47d82d18bd9

4937112194009 has 4 divisors (see below), whose sum is σ = 5196960204240. Its totient is φ = 4677264183780.

The previous prime is 4937112193969. The next prime is 4937112194033. The reversal of 4937112194009 is 9004912117394.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4937112194009 - 220 = 4937111145433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4937112194039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129924005087 + ... + 129924005124.

It is an arithmetic number, because the mean of its divisors is an integer number (1299240051060).

Almost surely, 24937112194009 is an apocalyptic number.

It is an amenable number.

4937112194009 is a deficient number, since it is larger than the sum of its proper divisors (259848010231).

4937112194009 is a wasteful number, since it uses less digits than its factorization.

4937112194009 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 259848010230.

The product of its (nonzero) digits is 489888, while the sum is 50.

The spelling of 4937112194009 in words is "four trillion, nine hundred thirty-seven billion, one hundred twelve million, one hundred ninety-four thousand, nine".

Divisors: 1 19 259848010211 4937112194009