Base | Representation |
---|---|
bin | 101101111111010110… |
… | …111100111110000001 |
3 | 11201110110202012000001 |
4 | 231333112330332001 |
5 | 1302113112113320 |
6 | 34404022000001 |
7 | 3365500444021 |
oct | 557726747601 |
9 | 151413665001 |
10 | 49381363585 |
11 | 19a40546394 |
12 | 96a1876001 |
13 | 486c84a588 |
14 | 25664d5a81 |
15 | 14403e520a |
hex | b7f5bcf81 |
49381363585 has 4 divisors (see below), whose sum is σ = 59257636308. Its totient is φ = 39505090864.
The previous prime is 49381363583. The next prime is 49381363601. The reversal of 49381363585 is 58536318394.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 18800797456 + 30580566129 = 137116^2 + 174873^2 .
It is a cyclic number.
It is not a de Polignac number, because 49381363585 - 21 = 49381363583 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49381363583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4938136354 + ... + 4938136363.
It is an arithmetic number, because the mean of its divisors is an integer number (14814409077).
Almost surely, 249381363585 is an apocalyptic number.
It is an amenable number.
49381363585 is a deficient number, since it is larger than the sum of its proper divisors (9876272723).
49381363585 is an equidigital number, since it uses as much as digits as its factorization.
49381363585 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9876272722.
The product of its digits is 9331200, while the sum is 55.
The spelling of 49381363585 in words is "forty-nine billion, three hundred eighty-one million, three hundred sixty-three thousand, five hundred eighty-five".
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