4940667131 has 4 divisors (see below), whose sum is σ = 5010254064. Its totient is φ = 4871080200.

The previous prime is 4940667101. The next prime is 4940667287. The reversal of 4940667131 is 1317660494.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4940667131 is a prime.

It is a super-3 number, since 3×4940667131³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4940667101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34793360 + ... + 34793501.

It is an arithmetic number, because the mean of its divisors is an integer number (1252563516).

Almost surely, 2^4940667131 is an apocalyptic number.

4940667131 is a deficient number, since it is larger than the sum of its proper divisors (69586933).

4940667131 is an equidigital number, since it uses as much as digits as its factorization.

4940667131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69586932.

The product of its (nonzero) digits is 108864, while the sum is 41.

The square root of 4940667131 is about 70289.8792928256. The cubic root of 4940667131 is about 1703.1851623832.

The spelling of 4940667131 in words is "four billion, nine hundred forty million, six hundred sixty-seven thousand, one hundred thirty-one".