Base | Representation |
---|---|
bin | 101110000001000111… |
… | …101010111100000001 |
3 | 11201112112100101210211 |
4 | 232001013222330001 |
5 | 1302143143141001 |
6 | 34410555154121 |
7 | 3366306552013 |
oct | 560107527401 |
9 | 151475311724 |
10 | 49410912001 |
11 | 19a56198570 |
12 | 96ab745941 |
13 | 48759c4b49 |
14 | 256a3c81b3 |
15 | 1442cd0351 |
hex | b811eaf01 |
49410912001 has 4 divisors (see below), whose sum is σ = 53902813104. Its totient is φ = 44919010900.
The previous prime is 49410911923. The next prime is 49410912013. The reversal of 49410912001 is 10021901494.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 49410912001 - 213 = 49410903809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49410912041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2245950535 + ... + 2245950556.
It is an arithmetic number, because the mean of its divisors is an integer number (13475703276).
Almost surely, 249410912001 is an apocalyptic number.
It is an amenable number.
49410912001 is a deficient number, since it is larger than the sum of its proper divisors (4491901103).
49410912001 is a wasteful number, since it uses less digits than its factorization.
49410912001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4491901102.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 49410912001 in words is "forty-nine billion, four hundred ten million, nine hundred twelve thousand, one".
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