Base | Representation |
---|---|
bin | 101110000101011000… |
… | …101010000001001001 |
3 | 11201201112000002210101 |
4 | 232011120222001021 |
5 | 1302320003123140 |
6 | 34422033045401 |
7 | 3401136041161 |
oct | 560530520111 |
9 | 151645002711 |
10 | 49482473545 |
11 | 19a9262583a |
12 | 970b6b6861 |
13 | 488778c35b |
14 | 2575ad55a1 |
15 | 144921899a |
hex | b8562a049 |
49482473545 has 4 divisors (see below), whose sum is σ = 59378968260. Its totient is φ = 39585978832.
The previous prime is 49482473543. The next prime is 49482473569. The reversal of 49482473545 is 54537428494.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6404640841 + 43077832704 = 80029^2 + 207552^2 .
It is a cyclic number.
It is not a de Polignac number, because 49482473545 - 21 = 49482473543 is a prime.
It is not an unprimeable number, because it can be changed into a prime (49482473543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4948247350 + ... + 4948247359.
It is an arithmetic number, because the mean of its divisors is an integer number (14844742065).
Almost surely, 249482473545 is an apocalyptic number.
It is an amenable number.
49482473545 is a deficient number, since it is larger than the sum of its proper divisors (9896494715).
49482473545 is an equidigital number, since it uses as much as digits as its factorization.
49482473545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9896494714.
The product of its digits is 19353600, while the sum is 55.
The spelling of 49482473545 in words is "forty-nine billion, four hundred eighty-two million, four hundred seventy-three thousand, five hundred forty-five".
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