Base | Representation |
---|---|
bin | 1001001101111011… |
… | …11000100011001001 |
3 | 110202212220012222212 |
4 | 10212331320203021 |
5 | 40113333131123 |
6 | 2135020154505 |
7 | 233430313340 |
oct | 44675704311 |
9 | 13685805885 |
10 | 4948723913 |
11 | 210a475581 |
12 | b61398a35 |
13 | 60b347703 |
14 | 34d354b57 |
15 | 1de6c8878 |
hex | 126f788c9 |
4948723913 has 4 divisors (see below), whose sum is σ = 5655684480. Its totient is φ = 4241763348.
The previous prime is 4948723909. The next prime is 4948724087. The reversal of 4948723913 is 3193278494.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4948723913 - 22 = 4948723909 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4948723313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353480273 + ... + 353480286.
It is an arithmetic number, because the mean of its divisors is an integer number (1413921120).
Almost surely, 24948723913 is an apocalyptic number.
It is an amenable number.
4948723913 is a deficient number, since it is larger than the sum of its proper divisors (706960567).
4948723913 is an equidigital number, since it uses as much as digits as its factorization.
4948723913 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 706960566.
The product of its digits is 1306368, while the sum is 50.
The square root of 4948723913 is about 70347.1670573876. The cubic root of 4948723913 is about 1704.1104584338.
The spelling of 4948723913 in words is "four billion, nine hundred forty-eight million, seven hundred twenty-three thousand, nine hundred thirteen".
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