Base | Representation |
---|---|
bin | 100100000010100010011… |
… | …1010100111010000110011 |
3 | 122112112012202100021221002 |
4 | 1020011010322213100303 |
5 | 1122123230344230042 |
6 | 14311254312552215 |
7 | 1020601145064650 |
oct | 110050472472063 |
9 | 18475182307832 |
10 | 4953253508147 |
11 | 163a73252431a |
12 | 67bb826b266b |
13 | 29c1223a91b9 |
14 | 131a4b1acc27 |
15 | 88ca37e9132 |
hex | 48144ea7433 |
4953253508147 has 8 divisors (see below), whose sum is σ = 5665287168000. Its totient is φ = 4242326352264.
The previous prime is 4953253508113. The next prime is 4953253508183. The reversal of 4953253508147 is 7418053523594.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4953253508147 - 212 = 4953253504051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4953253508092 and 4953253508101.
It is not an unprimeable number, because it can be changed into a prime (4953253508747) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 276616397 + ... + 276634302.
It is an arithmetic number, because the mean of its divisors is an integer number (708160896000).
Almost surely, 24953253508147 is an apocalyptic number.
4953253508147 is a deficient number, since it is larger than the sum of its proper divisors (712033659853).
4953253508147 is a wasteful number, since it uses less digits than its factorization.
4953253508147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 553251985.
The product of its (nonzero) digits is 18144000, while the sum is 56.
The spelling of 4953253508147 in words is "four trillion, nine hundred fifty-three billion, two hundred fifty-three million, five hundred eight thousand, one hundred forty-seven".
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