49613111415321 has 4 divisors (see below), whose sum is σ = 66150815220432. Its totient is φ = 33075407610212.

The previous prime is 49613111415289. The next prime is 49613111415349. The reversal of 49613111415321 is 12351411131694.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 49613111415321 - 2⁵ = 49613111415289 is a prime.

It is a super-2 number, since 2×49613111415321² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (49613111413321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8268851902551 + ... + 8268851902556.

It is an arithmetic number, because the mean of its divisors is an integer number (16537703805108).

Almost surely, 2^{49613111415321} is an apocalyptic number.

It is an amenable number.

49613111415321 is a deficient number, since it is larger than the sum of its proper divisors (16537703805111).

49613111415321 is a wasteful number, since it uses less digits than its factorization.

49613111415321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16537703805110.

The product of its digits is 77760, while the sum is 42.

The spelling of 49613111415321 in words is "forty-nine trillion, six hundred thirteen billion, one hundred eleven million, four hundred fifteen thousand, three hundred twenty-one".