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496503795313 = 4314977493959
BaseRepresentation
bin1110011100110011110…
…11101010111001110001
31202110120012111010001001
413032121323222321301
531113314432422223
61020031331242001
750604553424641
oct7163173527161
91673505433031
10496503795313
111816254a3139
1280286149301
1337a87a0cac6
141a060b72521
15cdadc259ad
hex7399eeae71

496503795313 has 8 divisors (see below), whose sum is σ = 511460136000. Its totient is φ = 481702442928.

The previous prime is 496503795311. The next prime is 496503795317. The reversal of 496503795313 is 313597305694.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 496503795313 - 21 = 496503795311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (496503795311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38740573 + ... + 38753386.

It is an arithmetic number, because the mean of its divisors is an integer number (63932517000).

Almost surely, 2496503795313 is an apocalyptic number.

496503795313 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

496503795313 is a deficient number, since it is larger than the sum of its proper divisors (14956340687).

496503795313 is a wasteful number, since it uses less digits than its factorization.

496503795313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77494151.

The product of its (nonzero) digits is 9185400, while the sum is 55.

The spelling of 496503795313 in words is "four hundred ninety-six billion, five hundred three million, seven hundred ninety-five thousand, three hundred thirteen".

Divisors: 1 43 149 6407 77493959 3332240237 11546599891 496503795313