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49697942153 = 443112184971
BaseRepresentation
bin101110010010001110…
…100110101010001001
311202021112110001011012
4232102032212222021
51303240133122103
634455251213305
73406363352426
oct562216465211
9152245401135
1049697942153
111a093213572
12976b8a7235
1348c0301382
142596582d4d
15145d0cb2d8
hexb923a6a89

49697942153 has 4 divisors (see below), whose sum is σ = 49810127568. Its totient is φ = 49585756740.

The previous prime is 49697942141. The next prime is 49697942227. The reversal of 49697942153 is 35124979694.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 49697942153 - 222 = 49693747849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49697942092 and 49697942101.

It is not an unprimeable number, because it can be changed into a prime (49697945153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56092043 + ... + 56092928.

It is an arithmetic number, because the mean of its divisors is an integer number (12452531892).

Almost surely, 249697942153 is an apocalyptic number.

It is an amenable number.

49697942153 is a deficient number, since it is larger than the sum of its proper divisors (112185415).

49697942153 is a wasteful number, since it uses less digits than its factorization.

49697942153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112185414.

The product of its digits is 14696640, while the sum is 59.

The spelling of 49697942153 in words is "forty-nine billion, six hundred ninety-seven million, nine hundred forty-two thousand, one hundred fifty-three".

Divisors: 1 443 112184971 49697942153