Base | Representation |
---|---|
bin | 101110010011000000… |
… | …011001111011111011 |
3 | 11202022110000022101001 |
4 | 232103000121323323 |
5 | 1303302003402433 |
6 | 34500435105431 |
7 | 3406612335055 |
oct | 562300317373 |
9 | 152273008331 |
10 | 49710997243 |
11 | 1a09a61aaa6 |
12 | 9774142277 |
13 | 48c2c2268b |
14 | 25981c08d5 |
15 | 145e30957d |
hex | b93019efb |
49710997243 has 4 divisors (see below), whose sum is σ = 49727743560. Its totient is φ = 49694250928.
The previous prime is 49710997211. The next prime is 49710997247. The reversal of 49710997243 is 34279901794.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49710997243 - 25 = 49710997211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49710997247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8368705 + ... + 8374642.
It is an arithmetic number, because the mean of its divisors is an integer number (12431935890).
Almost surely, 249710997243 is an apocalyptic number.
49710997243 is a deficient number, since it is larger than the sum of its proper divisors (16746317).
49710997243 is a wasteful number, since it uses less digits than its factorization.
49710997243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16746316.
The product of its (nonzero) digits is 3429216, while the sum is 55.
The spelling of 49710997243 in words is "forty-nine billion, seven hundred ten million, nine hundred ninety-seven thousand, two hundred forty-three".
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