Search a number
-
+
4972953 = 31657651
BaseRepresentation
bin10010111110000110011001
3100100122121110
4102332012121
52233113303
6254330533
760161256
oct22760631
910318543
104972953
112897287
1217b9a49
13105169b
1493642d
15683703
hex4be199

4972953 has 4 divisors (see below), whose sum is σ = 6630608. Its totient is φ = 3315300.

The previous prime is 4972951. The next prime is 4972969. The reversal of 4972953 is 3592794.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4972953 - 21 = 4972951 is a prime.

It is a d-powerful number, because it can be written as 48 + 92 + 76 + 25 + 94 + 53 + 314 .

It is a D-number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4972951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 828823 + ... + 828828.

It is an arithmetic number, because the mean of its divisors is an integer number (1657652).

Almost surely, 24972953 is an apocalyptic number.

It is an amenable number.

4972953 is a deficient number, since it is larger than the sum of its proper divisors (1657655).

4972953 is a wasteful number, since it uses less digits than its factorization.

4972953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1657654.

The product of its digits is 68040, while the sum is 39.

The square root of 4972953 is about 2230.0118833764. The cubic root of 4972953 is about 170.6887055652.

It can be divided in two parts, 497 and 2953, that multiplied together give a palindrome (1467641).

The spelling of 4972953 in words is "four million, nine hundred seventy-two thousand, nine hundred fifty-three".

Divisors: 1 3 1657651 4972953