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4974994795 = 5994998959
BaseRepresentation
bin1001010001000100…
…00110010101101011
3110211201022220212111
410220202012111223
540142044313140
62141355223151
7234166521001
oct45042062553
913751286774
104974994795
112123289251
12b6a147ab7
13613915204
14352a32a71
151e1b677ea
hex12888656b

4974994795 has 4 divisors (see below), whose sum is σ = 5969993760. Its totient is φ = 3979995832.

The previous prime is 4974994769. The next prime is 4974994807. The reversal of 4974994795 is 5974994794.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4974994795 - 27 = 4974994667 is a prime.

It is a super-3 number, since 3×49749947953 (a number of 30 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4974994795.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 497499475 + ... + 497499484.

It is an arithmetic number, because the mean of its divisors is an integer number (1492498440).

Almost surely, 24974994795 is an apocalyptic number.

4974994795 is a deficient number, since it is larger than the sum of its proper divisors (994998965).

4974994795 is an equidigital number, since it uses as much as digits as its factorization.

4974994795 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 994998964.

The product of its digits is 102876480, while the sum is 67.

The square root of 4974994795 is about 70533.6430010531. The cubic root of 4974994795 is about 1707.1206282460.

Subtracting 4974994795 from its reverse (5974994794), we obtain a palindrome (999999999).

The spelling of 4974994795 in words is "four billion, nine hundred seventy-four million, nine hundred ninety-four thousand, seven hundred ninety-five".

Divisors: 1 5 994998959 4974994795