Search a number
-
+
497613040001 = 7116462507013
BaseRepresentation
bin1110011110111000000…
…11000110100110000001
31202120102111201120200122
413033130003012212001
531123102414240001
61020333354230025
750644213023320
oct7173403064601
91676374646618
10497613040001
11182044652090
1280535725315
1337c037795cc
141a1281da0b7
15ce262d5b1b
hex73dc0c6981

497613040001 has 8 divisors (see below), whose sum is σ = 620400673344. Its totient is φ = 387750420720.

The previous prime is 497613039953. The next prime is 497613040037. The reversal of 497613040001 is 100040316794.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 497613040001 - 234 = 480433170817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (497613040091) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3231253430 + ... + 3231253583.

It is an arithmetic number, because the mean of its divisors is an integer number (77550084168).

Almost surely, 2497613040001 is an apocalyptic number.

It is an amenable number.

497613040001 is a deficient number, since it is larger than the sum of its proper divisors (122787633343).

497613040001 is a wasteful number, since it uses less digits than its factorization.

497613040001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6462507031.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 497613040001 its reverse (100040316794), we get a palindrome (597653356795).

The spelling of 497613040001 in words is "four hundred ninety-seven billion, six hundred thirteen million, forty thousand, one".

Divisors: 1 7 11 77 6462507013 45237549091 71087577143 497613040001