Base | Representation |
---|---|
bin | 101110011000001000… |
… | …010111010101000011 |
3 | 11202112102210011112122 |
4 | 232120020113111003 |
5 | 1303441011013140 |
6 | 34513145514455 |
7 | 3412005154646 |
oct | 563010272503 |
9 | 152472704478 |
10 | 49796969795 |
11 | 1a1341004a1 |
12 | 9798aa2a2b |
13 | 4907994401 |
14 | 25a579da5d |
15 | 1466b3cab5 |
hex | b98217543 |
49796969795 has 16 divisors (see below), whose sum is σ = 61155151200. Its totient is φ = 38905327104.
The previous prime is 49796969791. The next prime is 49796969801. The reversal of 49796969795 is 59796969794.
It is a cyclic number.
It is not a de Polignac number, because 49796969795 - 22 = 49796969791 is a prime.
It is not an unprimeable number, because it can be changed into a prime (49796969791) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1951781 + ... + 1977129.
It is an arithmetic number, because the mean of its divisors is an integer number (3822196950).
Almost surely, 249796969795 is an apocalyptic number.
49796969795 is a deficient number, since it is larger than the sum of its proper divisors (11358181405).
49796969795 is a wasteful number, since it uses less digits than its factorization.
49796969795 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34534.
The product of its digits is 2083248720, while the sum is 80.
Subtracting 49796969795 from its reverse (59796969794), we obtain a palindrome (9999999999).
The spelling of 49796969795 in words is "forty-nine billion, seven hundred ninety-six million, nine hundred sixty-nine thousand, seven hundred ninety-five".
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