Base | Representation |
---|---|
bin | 11101101100100… |
… | …110111100100001 |
3 | 1021201111212100120 |
4 | 131230212330201 |
5 | 2010021424441 |
6 | 121234510453 |
7 | 15226624461 |
oct | 3554467441 |
9 | 1251455316 |
10 | 498233121 |
11 | 23626aa11 |
12 | 11aa35429 |
13 | 7c2b6ac9 |
14 | 4a255ba1 |
15 | 2db19966 |
hex | 1db26f21 |
498233121 has 4 divisors (see below), whose sum is σ = 664310832. Its totient is φ = 332155412.
The previous prime is 498233119. The next prime is 498233149. The reversal of 498233121 is 121332894.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 498233121 - 21 = 498233119 is a prime.
It is a super-2 number, since 2×4982331212 = 496472485722801282, which contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (498233191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83038851 + ... + 83038856.
It is an arithmetic number, because the mean of its divisors is an integer number (166077708).
Almost surely, 2498233121 is an apocalyptic number.
It is an amenable number.
498233121 is a deficient number, since it is larger than the sum of its proper divisors (166077711).
498233121 is a wasteful number, since it uses less digits than its factorization.
498233121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166077710.
The product of its digits is 10368, while the sum is 33.
The square root of 498233121 is about 22321.1361941994. The cubic root of 498233121 is about 792.7645073679.
The spelling of 498233121 in words is "four hundred ninety-eight million, two hundred thirty-three thousand, one hundred twenty-one".
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