4994120433 has 16 divisors (see below), whose sum is σ = 6949975680. Its totient is φ = 3183907584.

The previous prime is 4994120423. The next prime is 4994120459. The reversal of 4994120433 is 3340214994.

4994120433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4994120433 - 2¹⁰ = 4994119409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4994120391 and 4994120400.

It is not an unprimeable number, because it can be changed into a prime (4994120423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 566185 + ... + 574937.

It is an arithmetic number, because the mean of its divisors is an integer number (434373480).

Almost surely, 2^4994120433 is an apocalyptic number.

It is an amenable number.

4994120433 is a deficient number, since it is larger than the sum of its proper divisors (1955855247).

4994120433 is a wasteful number, since it uses less digits than its factorization.

4994120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17048.

The product of its (nonzero) digits is 93312, while the sum is 39.

The square root of 4994120433 is about 70669.0910724059. The cubic root of 4994120433 is about 1709.3054225721.

The spelling of 4994120433 in words is "four billion, nine hundred ninety-four million, one hundred twenty thousand, four hundred thirty-three".