50001344311531 has 4 divisors (see below), whose sum is σ = 50004442112464. Its totient is φ = 49998246510600.

The previous prime is 50001344311453. The next prime is 50001344311543. The reversal of 50001344311531 is 13511344310005.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50001344311531 - 2³¹ = 49999196827883 is a prime.

It is a super-2 number, since 2×50001344311531² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50001344311493 and 50001344311502.

It is not an unprimeable number, because it can be changed into a prime (50001344311231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1548876255 + ... + 1548908536.

It is an arithmetic number, because the mean of its divisors is an integer number (12501110528116).

Almost surely, 2^{50001344311531} is an apocalyptic number.

50001344311531 is a deficient number, since it is larger than the sum of its proper divisors (3097800933).

50001344311531 is a wasteful number, since it uses less digits than its factorization.

50001344311531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3097800932.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 50001344311531 its reverse (13511344310005), we get a palindrome (63512688621536).

The spelling of 50001344311531 in words is "fifty trillion, one billion, three hundred forty-four million, three hundred eleven thousand, five hundred thirty-one".