Base | Representation |
---|---|
bin | 1001010100000111… |
… | …00101011011101001 |
3 | 110220111102021012001 |
4 | 10222003211123221 |
5 | 40220120100441 |
6 | 2144111051001 |
7 | 234626655220 |
oct | 45203453351 |
9 | 13814367161 |
10 | 5000550121 |
11 | 2136753356 |
12 | b76810a61 |
13 | 618cc20c8 |
14 | 3561a5cb7 |
15 | 1e4014731 |
hex | 12a0e56e9 |
5000550121 has 4 divisors (see below), whose sum is σ = 5714914432. Its totient is φ = 4286185812.
The previous prime is 5000550073. The next prime is 5000550143. The reversal of 5000550121 is 1210550005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5000550121 is a prime.
It is a super-3 number, since 3×50005501213 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5000550161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357182145 + ... + 357182158.
It is an arithmetic number, because the mean of its divisors is an integer number (1428728608).
Almost surely, 25000550121 is an apocalyptic number.
It is an amenable number.
5000550121 is a deficient number, since it is larger than the sum of its proper divisors (714364311).
5000550121 is an equidigital number, since it uses as much as digits as its factorization.
5000550121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 714364310.
The product of its (nonzero) digits is 250, while the sum is 19.
The square root of 5000550121 is about 70714.5679545594. The cubic root of 5000550121 is about 1710.0386572887.
The spelling of 5000550121 in words is "five billion, five hundred fifty thousand, one hundred twenty-one".
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