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50008314313 = 831765734123
BaseRepresentation
bin101110100100101110…
…100101000111001001
311210002011110120201101
4232210232211013021
51304404112024223
634550135421401
73420152441506
oct564456450711
9153064416641
1050008314313
111a232431791
129837824861
13493c6c1239
1425c58964ad
15147a4884ad
hexba4ba51c9

50008314313 has 8 divisors (see below), whose sum is σ = 50615173728. Its totient is φ = 49401558624.

The previous prime is 50008314311. The next prime is 50008314329. The reversal of 50008314313 is 31341380005.

50008314313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50008314313 - 21 = 50008314311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50008314311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1448470 + ... + 1482592.

It is an arithmetic number, because the mean of its divisors is an integer number (6326896716).

Almost surely, 250008314313 is an apocalyptic number.

It is an amenable number.

50008314313 is a deficient number, since it is larger than the sum of its proper divisors (606859415).

50008314313 is a wasteful number, since it uses less digits than its factorization.

50008314313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51863.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 50008314313 its reverse (31341380005), we get a palindrome (81349694318).

The spelling of 50008314313 in words is "fifty billion, eight million, three hundred fourteen thousand, three hundred thirteen".

Divisors: 1 83 17657 34123 1465531 2832209 602509811 50008314313