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500111006113 = 17771979142211
BaseRepresentation
bin1110100011100001111…
…00000101100110100001
31202210212121002102000001
413101300330011212201
531143211404143423
61021425310300001
751063134261335
oct7216074054641
91683777072001
10500111006113
11183106696a94
1280b121b7601
1338211146074
141a2c3c7b7c5
15d02075dcad
hex7470f059a1

500111006113 has 8 divisors (see below), whose sum is σ = 500648813280. Its totient is φ = 499573490880.

The previous prime is 500111006111. The next prime is 500111006137. The reversal of 500111006113 is 311600111005.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 500111006113 - 21 = 500111006111 is a prime.

It is a super-2 number, since 2×5001110061132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (500111006111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3445578 + ... + 3587788.

It is an arithmetic number, because the mean of its divisors is an integer number (62581101660).

Almost surely, 2500111006113 is an apocalyptic number.

It is an amenable number.

500111006113 is a deficient number, since it is larger than the sum of its proper divisors (537807167).

500111006113 is a wasteful number, since it uses less digits than its factorization.

500111006113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145967.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 500111006113 its reverse (311600111005), we get a palindrome (811711117118).

The spelling of 500111006113 in words is "five hundred billion, one hundred eleven million, six thousand, one hundred thirteen".

Divisors: 1 1777 1979 142211 3516683 252708947 281435569 500111006113