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50031404011 = 61820186951
BaseRepresentation
bin101110100110000110…
…101010001111101011
311210010202220122211101
4232212012222033223
51304431014412021
634552322342231
73420552626431
oct564606521753
9153122818741
1050031404011
111a244472386
1298434ba977
134944416a94
1425c8986d51
15147c4e9a91
hexba61aa3eb

50031404011 has 4 divisors (see below), whose sum is σ = 50851591024. Its totient is φ = 49211217000.

The previous prime is 50031404009. The next prime is 50031404021. The reversal of 50031404011 is 11040413005.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50031404011 - 21 = 50031404009 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 50031404011.

It is not an unprimeable number, because it can be changed into a prime (50031404021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410093415 + ... + 410093536.

It is an arithmetic number, because the mean of its divisors is an integer number (12712897756).

Almost surely, 250031404011 is an apocalyptic number.

50031404011 is a deficient number, since it is larger than the sum of its proper divisors (820187013).

50031404011 is an equidigital number, since it uses as much as digits as its factorization.

50031404011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 820187012.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 50031404011 its reverse (11040413005), we get a palindrome (61071817016).

The spelling of 50031404011 in words is "fifty billion, thirty-one million, four hundred four thousand, eleven".

Divisors: 1 61 820186951 50031404011