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50041211153 = 157318733829
BaseRepresentation
bin101110100110101100…
…000100100100010001
311210011110100220200212
4232212230010210101
51304441022224103
634553312453505
73421032163613
oct564654044421
9153143326625
1050041211153
111a249a6065a
12984684a295
13494646b91b
1425c9dbadb3
15147d2d57d8
hexba6b04911

50041211153 has 4 divisors (see below), whose sum is σ = 50359945140. Its totient is φ = 49722477168.

The previous prime is 50041211147. The next prime is 50041211173. The reversal of 50041211153 is 35111214005.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 19516928209 + 30524282944 = 139703^2 + 174712^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50041211153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50041211173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159366758 + ... + 159367071.

It is an arithmetic number, because the mean of its divisors is an integer number (12589986285).

Almost surely, 250041211153 is an apocalyptic number.

It is an amenable number.

50041211153 is a deficient number, since it is larger than the sum of its proper divisors (318733987).

50041211153 is a wasteful number, since it uses less digits than its factorization.

50041211153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318733986.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 50041211153 its reverse (35111214005), we get a palindrome (85152425158).

The spelling of 50041211153 in words is "fifty billion, forty-one million, two hundred eleven thousand, one hundred fifty-three".

Divisors: 1 157 318733829 50041211153