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50052344051 = 118709421639
BaseRepresentation
bin101110100111010110…
…100010100011110011
311210012020022112011102
4232213112202203303
51310001400002201
634554351235015
73421225622213
oct564726424363
9153166275142
1050052344051
111a2552749a6
12984a518a6b
134948869038
1425cb678243
15147e28426b
hexba75a28f3

50052344051 has 4 divisors (see below), whose sum is σ = 50052884400. Its totient is φ = 50051803704.

The previous prime is 50052344029. The next prime is 50052344087. The reversal of 50052344051 is 15044325005.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 15044325005 = 53008865001.

It is a cyclic number.

It is not a de Polignac number, because 50052344051 - 214 = 50052327667 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50052344021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92111 + ... + 329528.

It is an arithmetic number, because the mean of its divisors is an integer number (12513221100).

Almost surely, 250052344051 is an apocalyptic number.

50052344051 is a deficient number, since it is larger than the sum of its proper divisors (540349).

50052344051 is a wasteful number, since it uses less digits than its factorization.

50052344051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 540348.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 50052344051 its reverse (15044325005), we get a palindrome (65096669056).

The spelling of 50052344051 in words is "fifty billion, fifty-two million, three hundred forty-four thousand, fifty-one".

Divisors: 1 118709 421639 50052344051