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50080208035 = 5111370042249
BaseRepresentation
bin101110101001000000…
…110101010010100011
311210021011202011100211
4232221000311102203
51310031013124120
635001224354551
73422014513264
oct565100652243
9153234664324
1050080208035
111a269a76590
129857915a57
1349515739c0
1425d124c96b
15148193a25a
hexba90354a3

50080208035 has 16 divisors (see below), whose sum is σ = 70602588000. Its totient is φ = 33620279040.

The previous prime is 50080208033. The next prime is 50080208039. The reversal of 50080208035 is 53080208005.

It is not a de Polignac number, because 50080208035 - 21 = 50080208033 is a prime.

It is a super-3 number, since 3×500802080353 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 50080207988 and 50080208006.

It is not an unprimeable number, because it can be changed into a prime (50080208033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35020410 + ... + 35021839.

It is an arithmetic number, because the mean of its divisors is an integer number (4412661750).

Almost surely, 250080208035 is an apocalyptic number.

50080208035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

50080208035 is a deficient number, since it is larger than the sum of its proper divisors (20522379965).

50080208035 is a wasteful number, since it uses less digits than its factorization.

50080208035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70042278.

The product of its (nonzero) digits is 9600, while the sum is 31.

The spelling of 50080208035 in words is "fifty billion, eighty million, two hundred eight thousand, thirty-five".

Divisors: 1 5 11 13 55 65 143 715 70042249 350211245 770464739 910549237 3852323695 4552746185 10016041607 50080208035