Base | Representation |
---|---|
bin | 101110101010010100… |
… | …010111000001000011 |
3 | 11210022200221121011100 |
4 | 232222110113001003 |
5 | 1310102114313011 |
6 | 35003325545443 |
7 | 3422401600302 |
oct | 565224270103 |
9 | 153280847140 |
10 | 50102104131 |
11 | 1a280371432 |
12 | 9863115283 |
13 | 4955c6c181 |
14 | 25d410c439 |
15 | 1483812d56 |
hex | baa517043 |
50102104131 has 12 divisors (see below), whose sum is σ = 76178638120. Its totient is φ = 31643434080.
The previous prime is 50102104097. The next prime is 50102104153. The reversal of 50102104131 is 13140120105.
It is not a de Polignac number, because 50102104131 - 215 = 50102071363 is a prime.
It is a super-2 number, since 2×501021041312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50102104831) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 146497210 + ... + 146497551.
Almost surely, 250102104131 is an apocalyptic number.
50102104131 is a deficient number, since it is larger than the sum of its proper divisors (26076533989).
50102104131 is a wasteful number, since it uses less digits than its factorization.
50102104131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292994786 (or 292994783 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 50102104131 its reverse (13140120105), we get a palindrome (63242224236).
The spelling of 50102104131 in words is "fifty billion, one hundred two million, one hundred four thousand, one hundred thirty-one".
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