Base | Representation |
---|---|
bin | 1110100101010001110… |
… | …10011111110101000001 |
3 | 1202220022001011222221101 |
4 | 13102220322133311001 |
5 | 31202122312111340 |
6 | 1022102414454401 |
7 | 51125326456315 |
oct | 7225072376501 |
9 | 1686261158841 |
10 | 501050113345 |
11 | 1835487aa171 |
12 | 81134804401 |
13 | 38330882b12 |
14 | 1a372897b45 |
15 | d077e12c9a |
hex | 74a8e9fd41 |
501050113345 has 4 divisors (see below), whose sum is σ = 601260136020. Its totient is φ = 400840090672.
The previous prime is 501050113313. The next prime is 501050113363. The reversal of 501050113345 is 543311050105.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 269935319809 + 231114793536 = 519553^2 + 480744^2 .
It is a cyclic number.
It is not a de Polignac number, because 501050113345 - 25 = 501050113313 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50105011330 + ... + 50105011339.
It is an arithmetic number, because the mean of its divisors is an integer number (150315034005).
Almost surely, 2501050113345 is an apocalyptic number.
It is an amenable number.
501050113345 is a deficient number, since it is larger than the sum of its proper divisors (100210022675).
501050113345 is a wasteful number, since it uses less digits than its factorization.
501050113345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100210022674.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 501050113345 in words is "five hundred one billion, fifty million, one hundred thirteen thousand, three hundred forty-five".
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